How much voltage will develop across a 500-turn secondary from a primary of 2250 turns connected to 120 VAC?

How much voltage will develop across a 500-turn secondary from a primary of 2250 turns connected to 120 VAC?

• A. 12.5 volts
• B. 26.7 volts
• C. 50 volts
• D. 75 volts

Answer: (B)

To find the voltage that develops across the secondary winding of a transformer, you can use the transformer turns ratio, which relates the number of turns in the primary winding to the number of turns in the secondary winding. The formula to calculate the secondary voltage (\(V_s\)) is given by: \[ V_s = V_p \times \left(\frac{N_s}{N_p}\right) \] where: - \(V_p\) is the primary voltage (120 VAC in this case), - \(N_s\) is the number of turns in the secondary winding (500 turns), - \(N_p\) is the number of turns in the primary winding (2250 turns). Now substituting the values: \[ V_s = 120 \, \text{VAC} \times \left(\frac{500}{2250}\right) \] Calculating the turns ratio: \[ \frac{500}{2250} = \frac{1}{4.5} \approx 0.2222 \] Now applying this to find \(V_s\): \[ V_s = 120 \times 0.2222 \approx 26.67 \, \text{VAC}

To find the voltage that develops across the secondary winding of a transformer, you can use the transformer turns ratio, which relates the number of turns in the primary winding to the number of turns in the secondary winding. The formula to calculate the secondary voltage ((V_s)) is given by:

[

V_s = V_p \times \left(\frac{N_s}{N_p}\right)

]

where:

• (V_p) is the primary voltage (120 VAC in this case),

• (N_s) is the number of turns in the secondary winding (500 turns),

• (N_p) is the number of turns in the primary winding (2250 turns).

Now substituting the values:

[

V_s = 120 , \text{VAC} \times \left(\frac{500}{2250}\right)

]

Calculating the turns ratio:

[

\frac{500}{2250} = \frac{1}{4.5} \approx 0.2222

]

Now applying this to find (V_s):

[

V_s = 120 \times 0.2222 \approx 26.67 , \text{VAC}