What applied voltage is required for a 50 microampere meter movement with an internal resistance of 2,000 ohms to indicate half-scale deflection?

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Multiple Choice

What applied voltage is required for a 50 microampere meter movement with an internal resistance of 2,000 ohms to indicate half-scale deflection?

Explanation:
To determine the applied voltage required for the meter movement to indicate half-scale deflection, you can use Ohm's Law, which states that Voltage (V) equals Current (I) multiplied by Resistance (R). Since we're looking to achieve half-scale deflection for a meter that reads a maximum of 50 microamperes (uA), the current for half-scale deflection would be half of that: 25 uA. The internal resistance of the meter is given as 2,000 ohms. Applying Ohm's Law, we can calculate the required voltage: V = I × R = 25 uA × 2000 ohms First, convert 25 microamperes to amperes: 25 uA = 25 × 10^-6 A Now, substituting the values: V = (25 × 10^-6 A) × 2000 ohms = 0.05 volts Thus, the applied voltage required for the meter to indicate half-scale deflection is 0.05 volts, making the correct answer the second option. The remaining options represent voltages that do not match the meter's requirements for half-scale, either being too high or too low compared

To determine the applied voltage required for the meter movement to indicate half-scale deflection, you can use Ohm's Law, which states that Voltage (V) equals Current (I) multiplied by Resistance (R).

Since we're looking to achieve half-scale deflection for a meter that reads a maximum of 50 microamperes (uA), the current for half-scale deflection would be half of that: 25 uA. The internal resistance of the meter is given as 2,000 ohms.

Applying Ohm's Law, we can calculate the required voltage:

V = I × R

= 25 uA × 2000 ohms

First, convert 25 microamperes to amperes:

25 uA = 25 × 10^-6 A

Now, substituting the values:

V = (25 × 10^-6 A) × 2000 ohms

= 0.05 volts

Thus, the applied voltage required for the meter to indicate half-scale deflection is 0.05 volts, making the correct answer the second option. The remaining options represent voltages that do not match the meter's requirements for half-scale, either being too high or too low compared

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