What current will flow in a 6 volt storage battery with an internal resistance of 0.01 ohms when a 3-watt, 6-volt lamp is connected?

What current will flow in a 6 volt storage battery with an internal resistance of 0.01 ohms when a 3-watt, 6-volt lamp is connected?

• A. 0.25 amps
• B. 0.4995 amps
• C. 0.75 amps
• D. 1 amp

Answer: (B)

To determine the current flowing when a lamp is connected to the battery, we can apply Ohm's Law and the concept of total circuit resistance. First, we need to calculate the total resistance in the circuit, which includes the internal resistance of the battery and the resistance of the lamp. The power (P) of the lamp is given as 3 watts, and its voltage (V) is 6 volts. We can find the resistance (R) of the lamp using the formula: \[ P = \frac{V^2}{R} \] Rearranging the formula gives: \[ R = \frac{V^2}{P} \] Substituting in the values for the lamp: \[ R = \frac{6^2}{3} = \frac{36}{3} = 12 \text{ ohms} \] Next, we can find the total resistance in the circuit as the sum of the lamp's resistance and the internal resistance of the battery: \[ R_{total} = R_{lamp} + R_{internal} = 12 \text{ ohms} + 0.01 \text{ ohms} = 12.01 \text

To determine the current flowing when a lamp is connected to the battery, we can apply Ohm's Law and the concept of total circuit resistance.

First, we need to calculate the total resistance in the circuit, which includes the internal resistance of the battery and the resistance of the lamp. The power (P) of the lamp is given as 3 watts, and its voltage (V) is 6 volts. We can find the resistance (R) of the lamp using the formula:

[

P = \frac{V^2}{R}

]

Rearranging the formula gives:

[

R = \frac{V^2}{P}

]

Substituting in the values for the lamp:

[

R = \frac{6^2}{3} = \frac{36}{3} = 12 \text{ ohms}

]

Next, we can find the total resistance in the circuit as the sum of the lamp's resistance and the internal resistance of the battery:

[

R_{total} = R_{lamp} + R_{internal} = 12 \text{ ohms} + 0.01 \text{ ohms} = 12.01 \text