What is the maximum rated current-carrying capacity of a resistor marked "2000 ohms, 200 watts"?

What is the maximum rated current-carrying capacity of a resistor marked "2000 ohms, 200 watts"?

• A. 0.15 amps
• B. 0.25 amps
• C. 0.316 amps
• D. 0.5 amps

Answer: (C)

To determine the maximum rated current-carrying capacity of a resistor marked "2000 ohms, 200 watts," we can use the formula for power in terms of voltage and current, which is expressed as: \[ P = I^2 \times R \] where: - \( P \) is the power in watts, - \( I \) is the current in amperes, and - \( R \) is the resistance in ohms. We know the resistor's resistance (R) is \( 2000 \) ohms and the power (P) is \( 200 \) watts. We can rearrange the formula to find the current (I): \[ I = \sqrt{\frac{P}{R}} \] Substituting the known values into the formula: \[ I = \sqrt{\frac{200 \text{ watts}}{2000 \text{ ohms}}} \] This simplifies to: \[ I = \sqrt{0.1} = 0.316 \text{ amps} \] Thus, the maximum rated current-carrying capacity of the resistor is \( 0.316 \) amps. This indicates that at this current, the resistor can handle up to

To determine the maximum rated current-carrying capacity of a resistor marked "2000 ohms, 200 watts," we can use the formula for power in terms of voltage and current, which is expressed as:

[ P = I^2 \times R ]

where:

• ( P ) is the power in watts,

• ( I ) is the current in amperes, and

• ( R ) is the resistance in ohms.

We know the resistor's resistance (R) is ( 2000 ) ohms and the power (P) is ( 200 ) watts. We can rearrange the formula to find the current (I):

[ I = \sqrt{\frac{P}{R}} ]

Substituting the known values into the formula:

[ I = \sqrt{\frac{200 \text{ watts}}{2000 \text{ ohms}}} ]

This simplifies to:

[ I = \sqrt{0.1} = 0.316 \text{ amps} ]

Thus, the maximum rated current-carrying capacity of the resistor is ( 0.316 ) amps. This indicates that at this current, the resistor can handle up to