What is the total capacity required for a battery to run a 50W transmitter continuously for 6 hours with specified loads?

What is the total capacity required for a battery to run a 50W transmitter continuously for 6 hours with specified loads?

• A. 120 ampere-hours
• B. 150 ampere-hours
• C. 177 ampere-hours
• D. 200 ampere-hours

Answer: (C)

To determine the total capacity required for a battery to run a 50W transmitter continuously for 6 hours, we first need to calculate the total watt-hours needed. The power consumption of the transmitter is 50 watts, and it will run for 6 hours. Therefore, the total energy requirement in watt-hours can be calculated using the formula: \[ \text{Energy (Wh)} = \text{Power (W)} \times \text{Time (h)} \] Substituting in the values: \[ \text{Energy} = 50W \times 6h = 300Wh \] Next, we must convert watt-hours to ampere-hours, knowing that battery voltage will play a crucial role in this calculation. For common values, we often assume a nominal battery voltage of 12V. The formula to convert watt-hours to ampere-hours is: \[ \text{Ampere-hours (Ah)} = \frac{\text{Watt-hours (Wh)}}{\text{Voltage (V)}} \] Substituting in our values: \[ \text{Ampere-hours} = \frac{300Wh}{12V} = 25Ah \] However, the value

To determine the total capacity required for a battery to run a 50W transmitter continuously for 6 hours, we first need to calculate the total watt-hours needed.

The power consumption of the transmitter is 50 watts, and it will run for 6 hours. Therefore, the total energy requirement in watt-hours can be calculated using the formula:

[

\text{Energy (Wh)} = \text{Power (W)} \times \text{Time (h)}

]

Substituting in the values:

[

\text{Energy} = 50W \times 6h = 300Wh

]

Next, we must convert watt-hours to ampere-hours, knowing that battery voltage will play a crucial role in this calculation. For common values, we often assume a nominal battery voltage of 12V.

The formula to convert watt-hours to ampere-hours is:

[

\text{Ampere-hours (Ah)} = \frac{\text{Watt-hours (Wh)}}{\text{Voltage (V)}}

]

Substituting in our values:

[

\text{Ampere-hours} = \frac{300Wh}{12V} = 25Ah

]

However, the value